使用线性和非线性核的支持量回归（SVR）#

使用线性、多项和RBS核的1D回归的玩具示例。

# Authors: The scikit-learn developers
# SPDX-License-Identifier: BSD-3-Clause

import matplotlib.pyplot as plt
import numpy as np

from sklearn.svm import SVR

生成示例数据#

X = np.sort(5 * np.random.rand(40, 1), axis=0)
y = np.sin(X).ravel()

# add noise to targets
y[::5] += 3 * (0.5 - np.random.rand(8))

匹配回归模型#

svr_rbf = SVR(kernel="rbf", C=100, gamma=0.1, epsilon=0.1)
svr_lin = SVR(kernel="linear", C=100, gamma="auto")
svr_poly = SVR(kernel="poly", C=100, gamma="auto", degree=3, epsilon=0.1, coef0=1)

看结果#

lw = 2

svrs = [svr_rbf, svr_lin, svr_poly]
kernel_label = ["RBF", "Linear", "Polynomial"]
model_color = ["m", "c", "g"]

fig, axes = plt.subplots(nrows=1, ncols=3, figsize=(15, 10), sharey=True)
for ix, svr in enumerate(svrs):
    axes[ix].plot(
        X,
        svr.fit(X, y).predict(X),
        color=model_color[ix],
        lw=lw,
        label="{} model".format(kernel_label[ix]),
    )
    axes[ix].scatter(
        X[svr.support_],
        y[svr.support_],
        facecolor="none",
        edgecolor=model_color[ix],
        s=50,
        label="{} support vectors".format(kernel_label[ix]),
    )
    axes[ix].scatter(
        X[np.setdiff1d(np.arange(len(X)), svr.support_)],
        y[np.setdiff1d(np.arange(len(X)), svr.support_)],
        facecolor="none",
        edgecolor="k",
        s=50,
        label="other training data",
    )
    axes[ix].legend(
        loc="upper center",
        bbox_to_anchor=(0.5, 1.1),
        ncol=1,
        fancybox=True,
        shadow=True,
    )

fig.text(0.5, 0.04, "data", ha="center", va="center")
fig.text(0.06, 0.5, "target", ha="center", va="center", rotation="vertical")
fig.suptitle("Support Vector Regression", fontsize=14)
plt.show()

Total running time of the script: （0分4.769秒）