Name

ST_Disjoint — 如果栅格RASTA在空间上不与rastB相交,则返回TRUE。

Synopsis

boolean ST_Disjoint( raster rastA , integer nbandA , raster rastB , integer nbandB );

boolean ST_Disjoint( raster rastA , raster rastB );

描述

如果栅格RASTA和栅格B不共享任何空间,则它们是不相交的。如果未提供波段编号(或设置为空),则在测试中仅考虑栅格的凸包。如果提供了波段编号,则在测试中只考虑那些有值的像素(不考虑NODATA)。

[Note]

此函数不使用任何索引。

[Note]

要测试栅格和几何图形的空间关系,请在栅格上使用ST_Polygon,例如ST_DISCOCT(ST_Polygon(RASTER),GEOMETRY)。

可用性:2.1.0

示例

-- rid = 1 has no bands, hence the NOTICE and the NULL value for st_disjoint
SELECT r1.rid, r2.rid, ST_Disjoint(r1.rast, 1, r2.rast, 1) FROM dummy_rast r1 CROSS JOIN dummy_rast r2 WHERE r1.rid = 2;

NOTICE:  The second raster provided has no bands
 rid | rid | st_disjoint
-----+-----+-------------
   2 |   1 |
   2 |   2 | f
            
-- this time, without specifying band numbers
SELECT r1.rid, r2.rid, ST_Disjoint(r1.rast, r2.rast) FROM dummy_rast r1 CROSS JOIN dummy_rast r2 WHERE r1.rid = 2;

 rid | rid | st_disjoint
-----+-----+-------------
   2 |   1 | t
   2 |   2 | f
            

另请参阅

ST_Intersects